0.1x^2+10x=-520

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Solution for 0.1x^2+10x=-520 equation: 



0.1x^2+10x=-520

We move all terms to the left:

0.1x^2+10x-(-520)=0

We add all the numbers together, and all the variables

0.1x^2+10x+520=0

a = 0.1; b = 10; c = +520;
Δ = b2-4ac
Δ = 102-4·0.1·520
Δ = -108
Delta is less than zero, so there is no solution for the equation

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